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Question

Let $f(\theta ) = 3\left( {{{\sin }^4}\left( {{{3\pi } \over 2} - \theta } \right) + {{\sin }^4}(3\pi + \theta )} \right) - 2(1 - {\sin ^2}2\theta )$ and $S = \left\{ {\theta \in [0,\pi ]:f'(\theta ) = - {{\sqrt 3 } \over 2}} \right\}$. If $4\beta = \sum\limits_{\theta \in S} \theta $, then $f(\beta )$ is equal to

$\frac{9}{8}$
$\frac{3}{2}$
$\frac{5}{4}$
$\frac{11}{8}$

Solution

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