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Question

Let the tangents at the points $A(4,-11)$ and $B(8,-5)$ on the circle $x^{2}+y^{2}-3 x+10 y-15=0$, intersect at the point $C$. Then the radius of the circle, whose centre is $C$ and the line joining $A$ and $B$ is its tangent, is equal to :

$\frac{2\sqrt{13}}{3}$
$\frac{3\sqrt{3}}{4}$
$\sqrt{13}$
$2\sqrt{13}$

Solution

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