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Question

Let $x=2$ be a root of the equation $x^2+px+q=0$ and $$f(x) = \left\{ {\matrix{ {{{1 - \cos ({x^2} - 4px + {q^2} + 8q + 16)} \over {{{(x - 2p)}^4}}},} & {x \ne 2p} \cr {0,} & {x = 2p} \cr } } \right.$$

Then $\mathop {\lim }\limits_{x \to 2{p^ + }} [f(x)]$, where $\left[ . \right]$ denotes greatest integer function, is

2
1
0
$-1$

Solution

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