Two particles of equal mass '$m$' move in a circle of radius '$r$' under the action of their mutual gravitational attraction. The speed of each particle will be :

Question

$\sqrt{\frac{G m}{4 r}}$

$\sqrt{\frac{G m}{2 r}}$

$\sqrt{\frac{G m}{r}}$

$\sqrt{\frac{4 G m}{r}}$

Solution

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