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Question

Let the function $f(x) = 2{x^3} + (2p - 7){x^2} + 3(2p - 9)x - 6$ have a maxima for some value of $x < 0$ and a minima for some value of $x > 0$. Then, the set of all values of p is

$\left( { - {9 \over 2},{9 \over 2}} \right)$
$\left( {{9 \over 2},\infty } \right)$
$\left( {0,{9 \over 2}} \right)$
$\left( { - \infty ,{9 \over 2}} \right)$

Solution

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