A body of mass is taken from earth surface to the height h equal to twice the radius of earth (R$_e$), the increase in potential energy will be : (g = acceleration due to gravity on the surface of Earth)

Question

A body of mass is taken from earth surface to the height h equal to twice the radius of earth (R$_e$), the increase in potential energy will be :

(g = acceleration due to gravity on the surface of Earth)

$\frac{1}{2}mgR_e$

$3~mgR_e$

$\frac{1}{3}mgR_e$

$\frac{2}{3}mgR_e$

Please login to view the detailed solution steps...