The minimum value of the function $f(x) = \int\limits_0^2 {{e^{|x - t|}}dt} $ is : - DASH

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Question

The minimum value of the function $f(x) = \int\limits_0^2 {{e^{|x - t|}}dt} $ is :

2

$2(e-1)$

$e(e-1)$

$2e-1$

Solution

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