Electron beam used in an electron microscope, when accelerated by a voltage of 20 kV, has a de-Broglie wavelength of $\lambda_0$. IF the voltage is increased to 40 kV, then the de-Broglie wavelength associated with the electron beam would be :

Question

3 $\lambda_0$

9 $\lambda_0$

$\frac{\lambda_0}{\sqrt2}$

$\frac{\lambda_0}{2}$

Solution

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