Question
Let the six numbers $\mathrm{a_1,a_2,a_3,a_4,a_5,a_6}$, be in A.P. and $\mathrm{a_1+a_3=10}$. If the mean of these six numbers is $\frac{19}{2}$ and their variance is $\sigma^2$, then 8$\sigma^2$ is equal to :
Let the six numbers $\mathrm{a_1,a_2,a_3,a_4,a_5,a_6}$, be in A.P. and $\mathrm{a_1+a_3=10}$. If the mean of these six numbers is $\frac{19}{2}$ and their variance is $\sigma^2$, then 8$\sigma^2$ is equal to :