$\int\limits_{{{3\sqrt 2 } \over 4}}^{{{3\sqrt 3 } \over 4}} {{{48} \over {\sqrt {9 - 4{x^2}} }}dx} $ is equal to : - DASH

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Question

$\int\limits_{{{3\sqrt 2 } \over 4}}^{{{3\sqrt 3 } \over 4}} {{{48} \over {\sqrt {9 - 4{x^2}} }}dx} $ is equal to :

${\pi \over 2}$

${\pi \over 3}$

${\pi \over 6}$

$2\pi $

Solution

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