An $\alpha$-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength:
${\lambda _\alpha } > {\lambda _p} < {\lambda _e}$
${\lambda _\alpha } > {\lambda _p} > {\lambda _e}$
${\lambda _\alpha } = {\lambda _p} = {\lambda _e}$
${\lambda _\alpha } < {\lambda _p} < {\lambda _e}$
