The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by $\mathrm{{E_x} = {E_o}\sin (kz - \omega t)}$ $\mathrm{{B_y} = {B_o}\sin (kz - \omega t)}$ Then the correct relation between E$_0$ and B$_0$ is given by

Question

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

$\mathrm{{E_x} = {E_o}\sin (kz - \omega t)}$

$\mathrm{{B_y} = {B_o}\sin (kz - \omega t)}$

Then the correct relation between E$_0$ and B$_0$ is given by

$\mathrm{{E_o}{B_o} = \omega k}$

$\mathrm{{E_0} = k{B_0}}$

$\mathrm{k{E_0} = \omega {B_0}}$

$\mathrm{\omega {E_0} = k{B_0}}$

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