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Question

A metallic rod of length 'L' is rotated with an angular speed of '$\omega$' normal to a uniform magnetic field 'B' about an axis passing through one end of rod as shown in figure. The induced emf will be :

$\mathrm{\frac{1}{2}B^2L^2\omega}$
$\mathrm{\frac{1}{2}BL^2\omega}$
$\mathrm{\frac{1}{4}BL^2\omega}$
$\mathrm{\frac{1}{4}B^2L\omega}$

Solution

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