Question
Order of Covalent bond;
$\mathrm{A.~KF > KI ; LiF > KF}$
$\mathrm{B.~KF < KI ; LiF > KF}$
$\mathrm{C.~SnCl_4 > SnCl_2 ; CuCl > NaCl}$
$\mathrm{D.~LiF > KF ; CuCl < NaCl}$
$\mathrm{E.~KF < KI ; CuCl > NaCl}$
Choose the correct answer from the options given below :