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Question

Two long straight wires P and Q carrying equal current 10A each were kept parallel to each other at 5 cm distance. Magnitude of magnetic force experienced by 10 cm length of wire P is F$_1$. If distance between wires is halved and currents on them are doubled, force F$_2$ on 10 cm length of wire P will be:

$\frac{F_1}{8}$
10 F$_1$
$\frac{F_1}{10}$
8 F$_1$

Solution

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