Two identical thin metal plates has charge $q_{1}$ and $q_{2}$ respectively such that $q_{1}>q_{2}$. The plates were brought close to each other to form a parallel plate capacitor of capacitance C. The potential difference between them is :

Question

$\frac{\left(q_{1}+q_{2}\right)}{C}$

$\frac{\left(q_{1}-q_{2}\right)}{C}$

$\frac{\left(q_{1}-q_{2}\right)}{2 C}$

$\frac{2\left(q_{1}-q_{2}\right)}{C}$

Solution

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