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Question

$$ \mathrm{N}_{2(\mathrm{~g})}+3 \mathrm{H}_{2(\mathrm{~g})} \rightleftharpoons 2 \mathrm{NH}_{3(\mathrm{~g})} $$

$20 \mathrm{~g} \quad ~~~5 \mathrm{~g}$

Consider the above reaction, the limiting reagent of the reaction and number of moles of $\mathrm{NH}_{3}$ formed respectively are :

$\mathrm{H}_{2}, 1.42$ moles
$\mathrm{H}_{2}, 0.71$ moles
$\mathrm{N}_{2}, 1.42$ moles
$\mathrm{N}_{2}, 0.71$ moles

Solution

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