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Question

Let $\hat{a}$ and $\hat{b}$ be two unit vectors such that the angle between them is $\frac{\pi}{4}$. If $\theta$ is the angle between the vectors $(\hat{a}+\hat{b})$ and $(\hat{a}+2 \hat{b}+2(\hat{a} \times \hat{b}))$, then the value of $164 \,\cos ^{2} \theta$ is equal to :

$90+27 \sqrt{2}$
$45+18 \sqrt{2}$
$90+3 \sqrt{2}$
$54+90 \sqrt{2}$

Solution

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