The time period of oscillation of a simple pendulum of length L suspended from the roof of a vehicle, which moves without friction down an inclined plane of inclination $\alpha$, is given by :

Question

$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \cos \alpha)}$

$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \sin \alpha)}$

$2 \pi \sqrt{\mathrm{L} / \mathrm{g}}$

$2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \tan \alpha)}$

Solution

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