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Question

In an experiment to find out the diameter of wire using screw gauge, the following observations were noted :

(A) Screw moves $0.5 \mathrm{~mm}$ on main scale in one complete rotation

(B) Total divisions on circular scale $=50$

(C) Main scale reading is $2.5 \mathrm{~mm}$

(D) $45^{\text {th }}$ division of circular scale is in the pitch line

(E) Instrument has 0.03 mm negative error

Then the diameter of wire is :

2.92 mm
2.54 mm
2.98 mm
3.45 mm

Solution

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