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Question

$$ \text { Let } f(x)=a x^{2}+b x+c \text { be such that } f(1)=3, f(-2)=\lambda \text { and } $ $f(3)=4$. If $f(0)+f(1)+f(-2)+f(3)=14$, then $\lambda$$ is equal to :

$-$4
$\frac{13}{2}$
$\frac{23}{2}$
4

Solution

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