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Question

The area enclosed by the curves $y=\log _{e}\left(x+\mathrm{e}^{2}\right), x=\log _{e}\left(\frac{2}{y}\right)$ and $x=\log _{\mathrm{e}} 2$, above the line $y=1$ is:

$2+\mathrm{e}-\log _{\mathrm{e}} 2$
$1+e-\log _{e} 2$
$e-\log _{e} 2$
$1+\log _{e} 2$

Solution

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