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Question

At time $t=0$ a particle starts travelling from a height $7 \hat{z} \mathrm{~cm}$ in a plane keeping z coordinate constant. At any instant of time it's position along the $\hat{x}$ and $\hat{y}$ directions are defined as $3 \mathrm{t}$ and $5 \mathrm{t}^{3}$ respectively. At t = 1s acceleration of the particle will be

$-30 \hat{y}$
$30 \hat{y}$
$3 \hat{x}+15 \hat{y}$
$3 \hat{x}+15 \hat{y}+7 \hat{z}$

Solution

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