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Question

As shown in the figure, after passing through the medium 1 . The speed of light $v_{2}$ in medium 2 will be :

$\left(\right.$ Given $\mathrm{c}=3 \times 10^{8} \mathrm{~ms}^{-1}$ )

$1.0 \times 10^{8} \mathrm{~ms}^{-1}$
$0.5 \times 10^{8} \mathrm{~ms}^{-1}$
$1.5 \times 10^{8} \mathrm{~ms}^{-1}$
$3.0 \times 10^{8} \mathrm{~ms}^{-1}$

Solution

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