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Question

The correct decreasing order of energy for the orbitals having, following set of quantum numbers :

(A) n = 3, l = 0, m = 0

(B) n = 4, l = 0, m = 0

(C) n = 3, l = 1, m = 0

(D) n = 3, l = 2, m = 1

is :

(D) > (B) > (C) > (A)
(B) > (D) > (C) > (A)
(C) > (B) > (D) > (A)
(B) > (C) > (D) > (A)

Solution

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