A block of mass M slides down on a rough inclined plane with constant velocity. The angle made by the incline plane with horizontal is $\theta$. The magnitude of the contact force will be :

Question

$\mathrm{Mg} \cos \theta$

$\sqrt{\mathrm{Mg} \sin \theta+\mathrm{Mg} \cos \theta}$

$\operatorname{Mg} \sin \theta \sqrt{1+\mu}$

Solution

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