Let $$ I=\int_{\pi / 4}^{\pi / 3}\left(\frac{8 \sin x-\sin 2 x}{x}\right) d x $$. Then

Question

${\pi \over 2} < I < {{3\pi } \over 4}$

${\pi \over 5} < I < {{5\pi } \over {12}}$

${{5\pi } \over {12}} < I < {{\sqrt 2 } \over 3}\pi $

${{3\pi } \over 4} < I < \pi $

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