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Question

Hemoglobin contains $0.34 \%$ of iron by mass. The number of Fe atoms in $3.3 \mathrm{~g}$ of hemoglobin is

(Given: Atomic mass of Fe is $56 \,\mathrm{u}, \mathrm{N}_{\mathrm{A}}=6.022 \times 10^{23} \mathrm{~mol}^{-1}$.)

$1.21 \times 10^{5}$
$12.0 \times 10^{16}$
$1.21 \times 10^{20}$
$3.4 \times 10^{22}$

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