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Question

If the maximum value of $a$, for which the function $f_{a}(x)=\tan ^{-1} 2 x-3 a x+7$ is non-decreasing in $\left(-\frac{\pi}{6}, \frac{\pi}{6}\right)$, is $\bar{a}$, then $f_{\bar{a}}\left(\frac{\pi}{8}\right)$ is equal to :

$$ 8-\frac{9 \pi}{4\left(9+\pi^{2}\right)} $$
$8-\frac{4 \pi}{9\left(4+\pi^{2}\right)}$
$8\left(\frac{1+\pi^{2}}{9+\pi^{2}}\right)$
$8-\frac{\pi}{4}$

Solution

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