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Question

If $0 < x < {1 \over {\sqrt 2 }}$ and ${{{{\sin }^{ - 1}}x} \over \alpha } = {{{{\cos }^{ - 1}}x} \over \beta }$, then the value of $\sin \left( {{{2\pi \alpha } \over {\alpha + \beta }}} \right)$ is :

$4 \sqrt{\left(1-x^{2}\right)}\left(1-2 x^{2}\right)$
$4 x \sqrt{\left(1-x^{2}\right)}\left(1-2 x^{2}\right)$
$2 x \sqrt{\left(1-x^{2}\right)}\left(1-4 x^{2}\right)$
$4 \sqrt{\left(1-x^{2}\right)}\left(1-4 x^{2}\right)$

Solution

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