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Question

An ice cube of dimensions $60 \mathrm{~cm} \times 50 \mathrm{~cm} \times 20 \mathrm{~cm}$ is placed in an insulation box of wall thickness $1 \mathrm{~cm}$. The box keeping the ice cube at $0^{\circ} \mathrm{C}$ of temperature is brought to a room of temperature $40^{\circ} \mathrm{C}$. The rate of melting of ice is approximately :

(Latent heat of fusion of ice is $3.4 \times 10^{5} \mathrm{~J} \mathrm{~kg}^{-1}$ and thermal conducting of insulation wall is $0.05 \,\mathrm{Wm}^{-1 \circ} \mathrm{C}^{-1}$ )

$61 \times 10^{-3} \mathrm{~kg} \mathrm{~s}^{-1}$
$61 \times 10^{-5} \mathrm{~kg} \mathrm{~s}^{-1}$
$208 \mathrm{~kg} \mathrm{~s}^{-1}$
$30 \times 10^{-5} \mathrm{~kg} \mathrm{~s}^{-1}$

Solution

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