A parallel beam of light of wavelength $900 \mathrm{~nm}$ and intensity $100 \,\mathrm{Wm}^{-2}$ is incident on a surface perpendicular to the beam. The number of photons crossing $1 \mathrm{~cm}^{2}$ area perpendicular to the beam in one second is :

Question

$3 \times 10^{16}$

$4.5 \times 10^{16}$

$4.5 \times 10^{17}$

$4.5 \times 10^{20}$

Solution

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