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Question

The magnetic field of a plane electromagnetic wave is given by :

$$ \overrightarrow{\mathrm{B}}=2 \times 10^{-8} \sin \left(0.5 \times 10^{3} x+1.5 \times 10^{11} \mathrm{t}\right) \,\hat{j} \mathrm{~T}$$.

The amplitude of the electric field would be :

$6\, \mathrm{Vm}^{-1}$ along $x$-axis
$3\, \mathrm{Vm}^{-1}$ along $z$-axis
$6\, \mathrm{Vm}^{-1}$ along $z$-axis
$2 \times 10^{-8} \,\mathrm{Vm}^{-1}$ along $z$-axis

Solution

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