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Question

$$C{H_3} - C{H_2} - CN\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{Ether}^{C{H_3}MgBr}} A\buildrel {{H_3}{O^ + }} \over \longrightarrow B\mathrel{\mathop{\kern0pt\longrightarrow} \limits_{HCl}^{Zn - Hg}} C$$

The correct structure of C is

$C{H_3} - C{H_2} - C{H_2} - C{H_3}$
$C{H_3} - C{H_2} - CH = C{H_2}$

Solution

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