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Question

The shortest distance between the lines $\frac{x+7}{-6}=\frac{y-6}{7}=z$ and $\frac{7-x}{2}=y-2=z-6$ is :

$2 \sqrt{29}$
1
$\sqrt{\frac{37}{29}}$
$\frac{\sqrt{29}}{2}$

Solution

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