A drop of liquid of density $\rho$ is floating half immersed in a liquid of density ${\sigma}$ and surface tension $7.5 \times 10^{-4}$ Ncm$-$1. The radius of drop in $\mathrm{cm}$ will be : (g = 10 ms$-$2)

Question

A drop of liquid of density $\rho$ is floating half immersed in a liquid of density ${\sigma}$ and surface tension $7.5 \times 10^{-4}$ Ncm^$-$1. The radius of drop in $\mathrm{cm}$ will be :

(g = 10 ms^$-$2)

$$ \frac{15}{\sqrt{(2 \rho-\sigma)}} $$

$\frac{15}{\sqrt{(\rho-\sigma)}}$

$\frac{3}{2 \sqrt{(\rho-\sigma)}}$

$\frac{3}{20 \sqrt{(2 \rho-\sigma)}}$

Solution

Please login to view the detailed solution steps...

Go to DASH