$20 \mathrm{~mL}$ of $0.1\, \mathrm{M} \,\mathrm{NH}_{4} \mathrm{OH}$ is mixed with $40 \mathrm{~mL}$ of $0.05 \mathrm{M} \mathrm{HCl}$. The $\mathrm{pH}$ of the mixture is nearest to : (Given : $\mathrm{K}_{\mathrm{b}}\left(\mathrm{NH}_{4} \mathrm{OH}\right)=1 \times 10^{-5}, \log 2=0.30, \log 3=0.48, \log 5=0.69, \log 7=0.84, \log 11= 1.04)$

Question

$20 \mathrm{~mL}$ of $0.1\, \mathrm{M} \,\mathrm{NH}_{4} \mathrm{OH}$ is mixed with $40 \mathrm{~mL}$ of $0.05 \mathrm{M} \mathrm{HCl}$. The $\mathrm{pH}$ of the mixture is nearest to :

(Given : $\mathrm{K}_{\mathrm{b}}\left(\mathrm{NH}_{4} \mathrm{OH}\right)=1 \times 10^{-5}, \log 2=0.30, \log 3=0.48, \log 5=0.69, \log 7=0.84, \log 11= 1.04)$

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Solution

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