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Question

The area of the region given by

$A=\left\{(x, y): x^{2} \leq y \leq \min \{x+2,4-3 x\}\right\}$ is :

$\frac{31}{8}$
$\frac{17}{6}$
$\frac{19}{6}$
$\frac{27}{8}$

Solution

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