If xy4 attains maximum value at the point (x, y) on the line passing through the points (50 + $\alpha$, 0) and (0, 50 + $\alpha$), $\alpha$ > 0, then (x, y) also lies on the line :

Question

If xy⁴ attains maximum value at the point (x, y) on the line passing through the points (50 + $\alpha$, 0) and (0, 50 + $\alpha$), $\alpha$ > 0, then (x, y) also lies on the line :

y = 4x

x = 4y

y = 4x + $\alpha$

x = 4y $-$ $\alpha$

Solution

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