Let $\alpha$1, $\alpha$2 ($\alpha$1 < $\alpha$2) be the values of $\alpha$ fo the points ($\alpha$, $-$3), (2, 0) and (1, $\alpha$) to be collinear. Then the equation of the line, passing through ($\alpha$1, $\alpha$2) and making an angle of ${\pi \over 3}$ with the positive direction of the x-axis, is :

Question

Let $\alpha$₁, $\alpha$₂ ($\alpha$₁ < $\alpha$₂) be the values of $\alpha$ fo the points ($\alpha$, $-$3), (2, 0) and (1, $\alpha$) to be collinear. Then the equation of the line, passing through ($\alpha$₁, $\alpha$₂) and making an angle of ${\pi \over 3}$ with the positive direction of the x-axis, is :

$x - \sqrt 3 y - 3\sqrt 3 + 1 = 0$

$\sqrt 3 x - y + \sqrt 3 + 3 = 0$

$x - \sqrt 3 y + 3\sqrt 3 + 1 = 0$

$\sqrt 3 x - y + \sqrt 3 - 3 = 0$

Solution

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