If n main scale divisions coincide with (n + 1) vernier scale divisions. The least count of vernier callipers, when each centimetre on the main scale is divided into five equal parts, will be :

Question

${2 \over {n + 1}}$ mm

${5 \over {n + 1}}$ mm

${1 \over {2n}}$ mm

${1 \over {5n}}$ mm

Solution

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