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Question

In series RLC resonator, if the self inductance and capacitance become double, the new resonant frequency (f2) and new quality factor (Q2) will be :

(f1 = original resonant frequency, Q1 = original quality factor)

${f_2} = {{{f_1}} \over 2}$ and ${Q_2} = {Q_1}$
${f_2} = {f_1}$ and ${Q_2} = {{{Q_1}} \over {{Q_2}}}$
${f_2} = 2{f_1}$ and ${Q_2} = {Q_1}$
${f_2} = {f_1}$ and ${Q_2} = 2{Q_1}$

Solution

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