The value of $\mathop {\lim }\limits_{x \to 1} {{({x^2} - 1){{\sin }^2}(\pi x)} \over {{x^4} - 2{x^3} + 2x - 1}}$ is equal to:

Question

${{{\pi ^2}} \over 6}$

${{{\pi ^2}} \over 3}$

${{{\pi ^2}} \over 2}$

$\pi$²

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