The electric field at a point associated with a light wave is given by

E = 200 [sin (6 $\times$ 10¹⁵)t + sin (9 $\times$ 10¹⁵)t] Vm^$-$1

Given : h = 4.14 $\times$ 10^$-$15 eVs

If this light falls on a metal surface having a work function of 2.50 eV, the maximum kinetic energy of the photoelectrons will be