Question
The activation energy of one of the reactions in a biochemical process is 532611 J mol$-$1. When the temperature falls from 310 K to 300 K, the change in rate constant observed is k300 = x $\times$ 10$-$3 k310. The value of x is ____________.
[Given : $\ln 10 = 2.3$, R = 8.3 J K$-$1 mol$-$1]
Correct Answer
1