The area enclosed by y2 = 8x and y = $\sqrt2$ x that lies outside the triangle formed by y = $\sqrt2$ x, x = 1, y = 2$\sqrt2$, is equal to:

Question

The area enclosed by y² = 8x and y = $\sqrt2$ x that lies outside the triangle formed by y = $\sqrt2$ x, x = 1, y = 2$\sqrt2$, is equal to:

${{16\sqrt 2 } \over 6}$

${{11\sqrt 2 } \over 6}$

${{13\sqrt 2 } \over 6}$

${{5\sqrt 2 } \over 6}$

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