Let the mean and the variance of 5 observations x1, x2, x3, x4, x5 be ${24 \over 5}$ and ${194 \over 25}$ respectively. If the mean and variance of the first 4 observation are ${7 \over 2}$ and a respectively, then (4a + x5) is equal to:

Question

Let the mean and the variance of 5 observations x₁, x₂, x₃, x₄, x₅ be ${24 \over 5}$ and ${194 \over 25}$ respectively. If the mean and variance of the first 4 observation are ${7 \over 2}$ and a respectively, then (4a + x₅) is equal to:

Solution

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