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Question

Let b1b2b3b4 be a 4-element permutation with bi $\in$ {1, 2, 3, ........, 100} for 1 $\le$ i $\le$ 4 and bi $\ne$ bj for i $\ne$ j, such that either b1, b2, b3 are consecutive integers or b2, b3, b4 are consecutive integers. Then the number of such permutations b1b2b3b4 is equal to ____________.

Correct Answer
18915

Solution

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