A ball is spun with angular acceleration $\alpha$ = 6t2 $-$ 2t where t is in second and $\alpha$ is in rads$-$2. At t = 0, the ball has angular velocity of 10 rads$-$1 and angular position of 4 rad. The most appropriate expression for the angular position of the ball is :

Question

A ball is spun with angular acceleration $\alpha$ = 6t² $-$ 2t where t is in second and $\alpha$ is in rads^$-$2. At t = 0, the ball has angular velocity of 10 rads^$-$1 and angular position of 4 rad. The most appropriate expression for the angular position of the ball is :

${3 \over 2}{t^4} - {t^2} + 10t$

${{{t^4}} \over 2} - {{{t^3}} \over 3} + 10t + 4$

${{2{t^4}} \over 3} - {{{t^3}} \over 6} + 10t + 12$

$2{t^4} - {{{t^3}} \over 2} + 5t + 4$

Solution

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