Let [t] denote the greatest integer less than or equal to t. Then, the value of the integral $\int\limits_0^1 {[ - 8{x^2} + 6x - 1]dx} $ is equal to :

Question

$-$1

${{ - 5} \over 4}$

${{\sqrt {17} - 13} \over 8}$

${{\sqrt {17} - 16} \over 8}$

Solution

Please login to view the detailed solution steps...

Go to DASH